Organic Chemistry

We have learned that the reactions of aldehydes and ketones with alcohols and amines are all reversible and one application of this feature was the use of acetals as protecting groups for aldehydes and ketones:

 

 

The acetal group protects aldehydes and ketones in basic conditions during, for example, LiAlH4 or NaBH4 reduction or Grignard reactions after which it is removed by hydrolysis.

Remember, the hydrolysis is in equilibrium with the alcohol reaction, and to move the process forward, a large excess of water is used.

The question is the mechanism of the hydrolysis of acetals and that’s what we will be discussing in today’s post.

 

Acetal Hydrolysis Mechanism

The reaction starts by protonation of one of the oxygens converting the alkoxy group into a good leaving group which is then kicked out by the other oxygen:

 

The resulting oxonium ion is very electrophilic and is attacked by water forming a hemicacetal after a deprotonation:

 

 

In a similar manner, the second alkoxy group is protonated and expelled by the hydroxyl group forming a new oxonium ion which, this time, is a protonated ketone:

 

 

And in the last step, the final product ketone is formed by another proton transfer reaction:

 

 

Putting all this together gives us a summary for the acetal hydrolysis mechanism:

 

 

 

Is there an Easier Way To Predict the Products of Hydrolysis?

There are quite a few steps in this reaction but fortunately, you don’t need to remember all the steps in order to predict the structure of the aldehyde and ketone of an acetal hydrolysis.

Here is the shortcut; draw a line between each oxygen and the carbon they are connected to.

These are the bonds that are cleaved during the hydrolysis. Each oxygen is part of the (an) alcohol, and the carbon connected to them is the C=O carbon atom:

 

 

Additional examples of acetal as well as imine and enamine hydrolysis is covered in this practice problem set:

 

 

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