00:01
Determine which alcohol and which carboxylic acid are needed to produce each esther.
00:06
Our esther are right here, 123, so we'll label these as esther's are alcohol's are right here.
00:22
Kyand.
00:25
Our acids are right here at the bottom.
00:32
So let's take a look at esther number 1 and let's look at some of the shapes that we notice.
00:38
We notice that there is a ring.
00:42
That's this so there's a ring of carbon on 1 end.
00:47
We also know- or we can also see, that there is a double bonded oxygen, so we're going to want a focus on either an alcohol or an acid that has a ring so right so right now all we need to look at our c e, h and f now we only need 1 ring and we don't know right now if it's going to be an alcohol or an acid.
01:20
So let's take a look at some other things that we notice about our ester to help figure it this out.
01:28
If we notice coming off of the ring, it leads to 1 carbon and then off of that there is an op.
01:37
We can assume that this was once an oh, so we're going to want to find a ring that has a carbon coming off of it and then directly connecting to an oh.
01:51
So that means we will use alcohol e, because alcohol e has a ring.
01:58
It has 1 carbon coming off of it in a chain that immediately connects to and 0.
02:06
So our alcohol in this case for ester 1 is going to be e.
02:17
So now, let's look at the rest of our esther.
02:22
We can see that there is a double bonded oxygen and then 1234 more carbons coming off of it.
02:30
So we're going to want to find an acid that has a double bonded oxygen with 4 carbons coming off.
02:38
Well, let's check out g, because this 1 has a double bonded oxygen: it has 1234 carbons coming off and then the double bonded oxygen, so our acid is going to be g, so, let's cross out e and g as those are taken.
03:03
Now, let's look at ester 2 point again: we have a ring, so it's either going to be c h or f that we're going to be looking at and then immediately coming off of that ring is a double bonded oxygen.
03:19
That's connected to an oh! well! we have a ring and the double bonded oxygen connecting to, and oh so we're going to start as o 2 by using acid h.
03:34
Now, let's take a look at the rest of our molecule or esther.
03:42
We can see that it's connected to and o so we're going to have to be bonded to the o, h right there and then there's 12 carbons and then 2 methyl groups coming off of it.
03:55
So that means we're not going to look at a we're not going to look at f we're not going to look at c and we can try d or b we're not going to look at h or i because these are acids or j.
04:15
So we need to take a look at an alcohol, so that leaves b or d, so we have 12 carbons and then 2 methyl groups coming off...
6 comments
Calvin N.
July 5, 2023
The video explanation is unclear and difficult to follow making it hard to understand the concepts of Fischer Esterification
Steven C.
August 2, 2023
the lack of proper organization in the video leads to confusion, hindering the learning experience.
Brooke M.
August 11, 2023
the video fails to effectively demonstrate the procedure for determining the required alcohol and carboxylic acid for each ester making it less helpful for students
Sydney M.
September 12, 2023
The explanation lacks clarity and coherence making it challenging for viewers to grasp the essential information needed for the Fischer Esterification process.
John S.
October 28, 2023
Yo, this video is like a maze but I think I got the gist of it The dude breaks down which alcohol and acid are needed for each ester! Its like a puzzle game
Christopher H.
November 18, 2023
Thanks for breaking down the process of determining the alcohols and acids needed to produce the esters, Mr Glor! Definitely helped in figuring out which components to use for each one ure a chemistry superhero 🦸♂️事2! Your explanation of matching the fu