Consider the following pseudocode ALGO which takes as input an array A containing n integers. Assume that array indexing begins at 0. ALGO (A) 1: x = A[0] 2: p = -1 3: r = n 4: while (True){ do { 5: 6: 7: 8: 9: 10: 11: 10: 11: 12: 13: 14: 15:} p = p + 1 } while (A[p] < x) do { r = r - 1 } while (A[r] > x) if (p >= r ){ return r } exchange A[p] and A[r] 1. Suppose the input array is A = <10, 19, 9, 7, 12, 8, 5, 4, 11, 2, 6, 3>
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I need manual help in tracing at the end of the first iteration of the while loop of line 4 the integer at index 11 of A. (The Answer for reference is 10) but I can't seem to figure out how the program runs without using a compiler so I need handwritten explanation
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- Take an array of length n where all the numbers are nonnegative and unique. Find the element inthe array possessing the highest value. Split the element into two parts where the first part containsthe next highest value in the array and the second part holds the required additive entity to get thehighest value. Return the array index value. Consider the negative numbers as well.Input: [4, 8, 6, 3, 2]Output: [4, 6, 2, 6, 3, 2]9.). integer array nums and an integer k, return the length of the shortest non-empty subarray of nums with a sum of at least k. If there is no such subarray, return -1. A subarray is a contiguous part of an array. Example 1: Input: nums = [1], k = 1 Output: 1 Example 2: Input: nums = [1,2], k = 4 Output: -1 Example 3: Input: nums = [2,-1,2], k = 3 Output: 3.Write a program that fills an integer array of size 1000 with random positive integers between 1 and 10.Assume that each element represents a different city and the integers stored in the array represent thenumber of golds in those cities. The program traverses over the array and collects the golds at each city,starting from a random position. When the program visits a certain city, all of the golds are collected,and the visited element of the array becomes 0 (no gold is left at that city.) The journey continues withthe rule given below. If the position at the nth step is denoted by pn, and the number of golds at the citypn is denoted by gn,??+1 = {| ((??−1 + ?? + ??) ???1000|, ????? 2 = 0| ((??−1 + ?? − ??) ???1000|, ????? 2 = 1.The program continues visiting cities until the last three visited city has no gold.The program, at each visit, should print out the following information:• The current city index (pn).• The previous city index (pn-1).• The number of golds at the current city…
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- Suppose an array sorted in ascending order is rotated at some pivot unknownto you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).Find the minimum element. The complexity must be O(logN)You may assume no duplicate exists in the array."""def find_min_rotate(array): """ Finds the minimum element in a sorted array that has been rotated. """ low = 0 high = len(array) - 1 while low < high: mid = (low + high) // 2 if array[mid] > array[high]: low = mid + 1 else: high = mid return array[low] def find_min_rotate_recur(array, low, high): """ Finds the minimum element in a sorted array that has been rotated. """ mid = (low + high) // 2 if mid == low:.Given an array, find the next greater element for each element in the array, ifavailable. If not available, print the element itself. The next greater element y for anelement x in the array is the first element that is greater than x and occurs on its rightside. The next greater element of the right most element in an array is the elementitself.Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]. implement in pythonA unimodal array is an array that has a sequence of monotonically increasing integers followed by a sequence of monotonically decreasing integers, assuming all elements in the array are unique. Example: - A= {4, 5, 8, 9, 10, 11, 7, 3, 2, 1}: A is a unimodal array because there is an increasing sequence followed by a decreasing sequence and the maximum element is 11.- B= {11, 9, 8, 7, 5, 4, 3, 2, 1}: B is not a unimodal array because there is no increasing sequence It is simply a decreasing sequence and the maximum element is 11.- C= {1, 2, 3, 4, 5, 7, 8, 9, 11}: C is not a unimodal array because There is an increasing sequence, but there is no decreasing sequence and the maximum element is 11.a) Design an efficient algorithm with the lowest possible complexity to state whether a given array is unimodal or not, and explain why your algorithm is efficient. b) Analyze the complexity of your algorithm. Data Structure With Python
- An array having a character subscript can be indexed using a computer language, as in CHR_ARRAY['A':'D']. In this scenario, the characters' ordinal numbers (ORDs), such as ORD('A') = 1, ORD('B') = 2, ORD('Z') = 26 and so on, are used to designate the array's elements, CHR_ARRAY['A'], CHR_ARRAY['B'], and so on. Beginning at position 500, two arrays called TEMP[1:5, -1:2] and CODE['A':'Z', 1:2] are now kept in the RAM. Furthermore, CODE outperforms TEMP in storage. Determine the locations of the following addresses: (i) TEMP[5, -1], (ii) CODE['N',2], and (iii) CODE['Z',1].Given an array, find the next greater element for each element in the array, ifavailable. If not available, print the element itself. The next greater element y for anelement x in the array is the first element that is greater than x and occurs on its rightside. The next greater element of the right most element in an array is the elementitself.Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]A computer language allows for array indexing with character subscripts, such as CHR_ARRAY['A':'D']. In this example, the array members are CHR_ARRAY['A'], CHR_ARRAY['B'], and so on, and the index is denoted by the ordinal number (ORD) of the characters, namely, ORD('A') = 1, ORD('B') = 2, ORD('Z') = 26, and so on.62 A Data Structures and Algorithms Textbook 1Beginning at position 500, two arrays TEMP[1:5, -1:2] and CODE['A':'Z', 1:2] are now kept in memory. Furthermore, CODE supersedes TEMP in storage. Determine the locations of (i) TEMP[5, -1], (ii) CODE['N',2], and (iii) CODE['Z',1].